What will be the output of following code ?<br /> <br /> Base Interface<br /> <br /> public interface BaseInterface {<br />    int i = 4;<br /> }<br /> <br /> Derived Interfaces<br /> <br /> public interface DerivedInterface1 extends BaseInterface{<br />    int i = 5;<br /> }<br /> <br /> public interface DerivedInterface2 extends BaseInterface{<br />    int i=6;<br /> }<br /> <br /> Implementing Class<br /> <br /> public class Class implements DerivedInterface1,DerivedInterface2 {<br />    public static void main(String[] args){<br />       System.out.println(BaseInterface.i);<br />    }<br /> }<br /> <br /> What will be the output upon executing main and Why ?
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 Q1. What will be the output of following code ?

Base Interface

public interface BaseInterface {
   int i = 4;
}

Derived Interfaces

public interface DerivedInterface1 extends BaseInterface{
   int i = 5;
}

public interface DerivedInterface2 extends BaseInterface{
   int i=6;
}

Implementing Class

public class Class implements DerivedInterface1,DerivedInterface2 {
   public static void main(String[] args){
      System.out.println(BaseInterface.i);
   }
}

What will be the output upon executing main and Why ?
Core Java
Ans. It will print 4 because member elements of an interface are implicitly static and hence the concept of overriding doesn't work.


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