What will be the output of following code ?<br /> class BuggyBread2 {       <br />    private static int counter = 0;     <br />    void BuggyBread2() {        <br />       counter = 5;    <br />    }     <br />    <br />    BuggyBread2(int x){<br />       counter = x;    <br />    }        <br /> <br />    public static void main(String[] args) {        <br />       BuggyBread2 bg = new BuggyBread2();        <br />       System.out.println(counter);    <br />    } <br /> }
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 Q1. What will be the output of following code ?
class BuggyBread2 {       
   private static int counter = 0;     
   void BuggyBread2() {        
      counter = 5;    
   }     
   
   BuggyBread2(int x){
      counter = x;    
   }        

   public static void main(String[] args) {        
      BuggyBread2 bg = new BuggyBread2();        
      System.out.println(counter);    
   } 
}
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Ans.  Compile time error as it won't find the constructor matching BuggyBread2(). 
Compiler won't provide default no argument constructor as programmer has already defined one constructor. 
Compiler will treat user defined BuggyBread2() as a method, as return type ( void ) has been specified for that. 

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