Will it print the message in Base Class constructor if we execute main method of Main class ? why ?<br /> <br /> public class BaseClass {<br /> BaseClass(){<br /> System.out.println("Hello I am in Base Class Constructor");<br /> }<br /> }<br /> <br /> public class DerivedClass extends BaseClass{<br /> }<br /> <br /> public class Main {<br /> <br /> public static void main(String[] args) {<br /> DerivedClass derivedClass = new DerivedClass();<br /> }<br /> }

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Q1. Will it print the message in Base Class constructor if we execute main method of Main class ? why ?

public class BaseClass {
BaseClass(){
System.out.println("Hello I am in Base Class Constructor");
}
}

public class DerivedClass extends BaseClass{
}

public class Main {

public static void main(String[] args) {
DerivedClass derivedClass = new DerivedClass();
}
}

Ans. Yes.

When the Derived class constructor is initialized , a no argument super will be called intrinsically.

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