What is the problem with this code ? class BuggyBread1 { private BuggyBread2 buggybread2; public static void main(String[] args){ try { BuggyBread1 buggybread1 = new BuggyBread1(); ObjectOutputStream objectOutputStream = new ObjectOutputStream(new FileOutputStream(new File("newFile.txt"))); objectOutputStream.writeObject(buggybread1); } catch (Exception e) { e.printStackTrace(); } } }

Interview Questions and Answers

Q1. What is the problem with this code ?

class BuggyBread1 {

private BuggyBread2 buggybread2;

public static void main(String[] args){
try {
BuggyBread1 buggybread1 = new BuggyBread1();
ObjectOutputStream objectOutputStream = new ObjectOutputStream(new FileOutputStream(new File("newFile.txt")));
objectOutputStream.writeObject(buggybread1);
} catch (Exception e) {
e.printStackTrace();
}
}
}

Core Java

Ans. Though we are trying to serialize BuggyBread1 object but we haven't declared the class to implement Serializable.

This will throw java.io.NotSerializableException upon execution.

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