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 Q61. Write a Program to print the positive and negative numbers separetlyCore Java
Ans. int[] arr = {1,-1,2,-3,3,-4,4,5,6,-5,-6,-7,-8,8,9,-9};
List positiveNumbers = new ArrayList<>();
List negativeNumbers = new ArrayList<>();
for(int i = 0; i < arr.length(); i ){
if(I < 0){
negativeNumbers.add(i);
} else {
positiveNumbers.add(i);
}
}

System.out.println("Positive Numbers:" + positiveNumbers);
System.out.println("Negative Numbers:" + negativeNumbers);

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 Q62. Implement the following method ?

int findMax(int[] items)
Core Java
Ans. int findMax(int[] items){
   int maxNumber = 0;
   for(int x:items){
      if(x > maxNumber){
         maxNumber = x;
      }
   }
      
   return maxNumber;
}

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 Q63. Write a Program to add 1-100, 101-200, 201-300 in different threads and then sum the numbers ?Core Java
Ans. public class TotalUsingThreads extends Thread{
   
   private static List<TotalUsingThreads> collector = new ArrayList<TotalUsingThreads>();
   
   private int startFrom = 0;
   
   private Integer threadTotal = null;
   
   Test(int startFrom){
      this.startFrom = startFrom;
   }
   
   
   public static void main(String[] args) throws InterruptedException{
      int totalSum = 0;
      
      // Create all the threads and set the count starting point for all of them
      for(int count=0;count<10;count++){
         TotalUsingThreads newThread = new TotalUsingThreads(count*100);
         newThread.start();
         collector.add(newThread);
      }
      
      boolean allCollected = false;
      
      
      // Make sure that all thread totals are collected and all threads have completed their tasks
      while(!allCollected){
         for(int count=0;count<10;count++){
            if(collector.get(count).threadTotal == null){
               Thread.sleep(100);
               break;
            }
         }
         allCollected = true;
      }
      
      // sum totals of all threads
      for(int count=0;count<10;count++){
         totalSum += collector.get(count).threadTotal;
      }
      
      System.out.println(totalSum);
      
      
   }
   
   public void run(){
      threadTotal = 0;
      for(int count=startFrom;count<startFrom+100;count++){
       threadTotal += count;   
      }
   }
}

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 Q64. How would you count the number of words in a string consisting of uneven number of spaces between words( not dictionary words)? With and without library functions.Core Java
Ans. package com.string;

import java.util.Scanner;

public class String13 {
public static void main(String[] args) {
System.out.println("Enter Sentence");
Scanner sc=new Scanner(System.in);
String sentence=sc.nextLine();
String[] words=sentence.split(" ");
int count=0;
for (String string : words) {
string.trim();
if(!string.equals("")){
count++;
System.out.println(string " " count);
}
}
}
}

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 Q65. Write a Java Program to check Armstrong Number ?Core Java
Ans. http://www.programmingsimplified.com/java/source-code/java-program-armstrong-number

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 Q66. What is the problem with following code ?

public static void main(String[] args) {
int x = 5;
return x*2;

int y = 10;
return y*2;

}
Ans. There are many problems with the code

1. The method returns void and hence we cannot return any integer value.

2. We cannot return more than one value from a method.

3. The code after 1st Return statement is unreachable.

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 Q67. What will this code print ?

String a = new String ("TEST");
String b = new String ("TEST");
if(a == b) {
System.out.println ("TRUE");
} else {
System.out.println ("FALSE");
}		Core Java
Ans. FALSE. == operator compares object references, a and b are references to two different objects, hence the FALSE. .equals method is used to compare string object content.

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 Q68. How many bits are used to represent Unicode, ASCII, UTF-16, and UTF-8 characters?
Ans. Unicode requires 16 bits and ASCII require 7 bits. Although the ASCII character set uses only 7 bits, it is usually represented as 8 bits. UTF-8 represents characters using 8, 16, and 18 bit patterns. UTF-16 uses 16-bit and larger bit patterns.

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 Q69. What is unicode ?Core Java
Ans. A way of encoding characters as binary numbers. The Unicode character set includes
characters used in many languages, not just English. Unicode is the character set that is
used internally by Java.

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 Q70. Write a method to convert binary to a number ?Core Java
Ans.
convert(int binaryInt) {
   int sumValue=0;
   int multiple = 1;
   while(binaryInt > 0){
      binaryDigit = binaryInt%10;
      binaryInt = binaryInt /10;
      sumValue = sumValue + (binaryDigit * multiple);
      multiple = multiple * 2;
   }
   return sumValue;
}

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 Q71. What will be the output of the following code ?

String s1 = "Buggy Bread";
String s2 = "Buggy Bread";
if(s1 == s2)
   System.out.println("equal 1");
String n1 = new String("Buggy Bread");
String n2 = new String("Buggy Bread");
if(n1 == n2)
   System.out.println("equal 2");		Core Java
Ans. equal 1

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 Q72. How to find whether a given integer is odd or even without use of modulus operator in java?Core Java
Ans. public static void main(String ar[])
{
int n=5;
if((n/2)*2==n)
{
System.out.println("Even Number ");
}
else
{
System.out.println("Odd Number ");
}
}

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 Q73. What will be the output of following Code ?

class BuggyBread {
   public static void main(String[] args) {
      String s2 = "I am unique!";
      String s5 = "I am unique!";

      System.out.println(s2 == s5);
   }
}		Core Java
Ans. true, due to String Pool, both will point to a same String object.

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 Q74. What will be the output of following code ?
class BuggyBread2 {       
   private static int counter = 0;     
   void BuggyBread2() {        
      counter = 5;    
   }     
   
   BuggyBread2(int x){
      counter = x;    
   }        

   public static void main(String[] args) {        
      BuggyBread2 bg = new BuggyBread2();        
      System.out.println(counter);    
   } 
}		Core Java
Ans.  Compile time error as it won't find the constructor matching BuggyBread2(). 
Compiler won't provide default no argument constructor as programmer has already defined one constructor. 
Compiler will treat user defined BuggyBread2() as a method, as return type ( void ) has been specified for that. 

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 Q75. what will be the output of this code ?

public static void main(String[] args){
   StringBuffer s1=new StringBuffer("Buggy");                       
   test(s1);                    
   System.out.println(s1);              
}       

private static void test(StringBuffer s){      
   s.append("Bread");   
}		Core Java
Ans.  BuggyBread

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 Q76. what will be the output of this code ?

public static void main(String[] args)    {          
   String s1=new String("Buggy");                         
   test(s1);                    
   System.out.println(s1);              
}       

private static void test(StringBuffer s){      
   s.append("Bread");   
}		Core Java
Ans.  Buggy

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 Q77. what will be the output of this code ?

public static void main(String[] args)    {          
   StringBuffer s1=new StringBuffer("Buggy");                         
   test(s1);                    
   System.out.println(s1);              
}       

private static void test(StringBuffer s){      
   s=new StringBuffer("Bread");   
}		Core Java
Ans.  Buggy

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 Q78. what will be the output ?

class Animal {
public void eat() throws Exception {
}
}

class Dog2 extends Animal {
public void eat(){}
public static void main(){
Animal an = new Dog2();
an.eat();
}
}		Core Java
Ans. Compile Time Error: Unhandled exception type Exception

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 Q79. What will the following code print when executed on Windows ?

public static void main(String[] args){
String parent = null;
File file = new File("/file.txt");
System.out.println(file.getPath());
System.out.println(file.getAbsolutePath());
try {
System.out.println(file.getCanonicalPath());
} catch (IOException e) {
e.printStackTrace();
}
}		Core Java
Ans. file.txtC:file.txtC:file.txt

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 Q80. What will be the output of following code ?

public static void main(String[] args){
String name = null;
File file = new File("/folder", name);
System.out.print(file.exists());
}		Core Java
Ans. NullPointerException

at line: "File file = new File("/folder", name);"

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 Q81. What will be the output of following code ?

public static void main(String[] args){
String parent = null;
File file = new File(parent, "myfile.txt");
try {
file.createNewFile();
} catch (IOException e) {
e.printStackTrace();
}
}		Core Java
Ans. It will create the file myfile.txt in the current directory.

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 Q82. What will be the output of following code ?

public static void main(String[] args){
String child = null;
File file = new File("/folder", child);
try {
file.createNewFile();
} catch (IOException e) {
e.printStackTrace();
}
}		Core Java
Ans. NullPointerException at line:File file = new File("/folder", child);

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 Q83. What will be the output of following code, assuming that currently we are in c:Project ?

public static void main(String[] args){
String child = null;
File file = new File("../file.txt");
System.out.println(file.getPath());
System.out.println(file.getAbsolutePath());
try {
System.out.println(file.getCanonicalPath());
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}		Core Java
Ans. ..file.txt
C:WorkspaceProject..file.txt
C:Workspacefile.txt

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 Q84. Which of the following code is correct ?

a.


FileWriter fileWriter = new FileWriter("../file.txt");
File file = new File(fileWriter );
BufferedWriter bufferedOutputWriter = new BufferedWriter(fileWriter);

b.

BufferedWriter bufferedOutputWriter = new BufferedWriter("../file.txt");
File file = new File(bufferedOutputWriter );
FileWriter fileWriter = new FileWriter(file);


c.

File file = new File("../file.txt");
FileWriter fileWriter = new FileWriter(file);
BufferedWriter bufferedOutputWriter = new BufferedWriter(fileWriter);

d.

File file = new File("../file.txt");
BufferedWriter bufferedOutputWriter = new BufferedWriter(file);
FileWriter fileWriter = new FileWriter(bufferedOutputWriter );		Core Java
Ans. c.

File file = new File("../file.txt");
FileWriter fileWriter = new FileWriter(file);
BufferedWriter bufferedOutputWriter = new BufferedWriter(fileWriter);

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 Q85. Which exception should be handled in the following code ?

File file = new File("../file.txt");
FileWriter fileWriter = new FileWriter(file);		Core Java
Ans. IOException

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 Q86. Which exceptions should be handled with the following code ?

FileOutputStream fileOutputStream = new FileOutputStream(new File("newFile.txt"));
Ans. FileNotFoundException

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 Q87. Will this code compile fine ?

ObjectOutputStream objectOutputStream = new ObjectOutputStream(new FileOutputStream(new File("newFile.txt")));		Core Java
Ans. Yes.

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 Q88. What is the problem with this code ?

class BuggyBread1 {

private BuggyBread2 buggybread2;

public static void main(String[] args){
try {
BuggyBread1 buggybread1 = new BuggyBread1();
ObjectOutputStream objectOutputStream = new ObjectOutputStream(new FileOutputStream(new File("newFile.txt")));
objectOutputStream.writeObject(buggybread1);
} catch (Exception e) {
e.printStackTrace();
}
}
}		Core Java
Ans. Though we are trying to serialize BuggyBread1 object but we haven't declared the class to implement Serializable.

This will throw java.io.NotSerializableException upon execution.

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 Q89. Will this code run fine if BuggyBread2 doesn't implement Serializable interface ?

class BuggyBread1 implements Serializable{
private BuggyBread2 buggybread2 = new BuggyBread2();

public static void main(String[] args){
try {
BuggyBread1 buggybread1 = new BuggyBread1();
ObjectOutputStream objectOutputStream = new ObjectOutputStream(new FileOutputStream(new File("newFile.txt")));
objectOutputStream.writeObject(buggybread1);
} catch (Exception e) {
e.printStackTrace();
}
}
}		Core Java
Ans. No, It will throw java.io.NotSerializableException.

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 Q90. Will this code work fine if BuggyBread2 doesn't implement Serializable ?

class BuggyBread1 extends BuggyBread2 implements Serializable{
private int x = 5;

public static void main(String[] args){
try {
BuggyBread1 buggybread1 = new BuggyBread1();
ObjectOutputStream objectOutputStream = new ObjectOutputStream(new FileOutputStream(new File("newFile.txt")));
objectOutputStream.writeObject(buggybread1);
} catch (Exception e) {
e.printStackTrace();
}
}
}		Core Java
Ans. Yes.

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