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Core Java - Interview Questions and Answers for '.equals' - 3 question(s) found - Order By Newest

 Q1. What will be the output of following Code ?

class BuggyBread {
   public static void main(String[] args) {
      String s2 = "I am unique!";
      String s5 = "I am unique!";

      System.out.println(s2 == s5);
   }
}
Core Java
Admin
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Ans. true, due to String Pool, both will point to a same String object.

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Related Questions

  Difference between == and .equals() ?
 why is "".equals(str); safer than str.equals("")?


 Q2. What is wrong with the following if statement ?

if(x==y && x.equals(y) {
}
Core Java2016-07-28 13:45:21

Ans. x==y means that both references have same type and are pointing to same memory location and hence would always mean that they have same value.

x.equals(y) is not required in this case.

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   Like         Discuss         Correct / Improve     if statement  control statements  == and equals  ==  .equals   code optimization

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Related Questions

  Difference between == and .equals() ?
 What is the difference between = and == in Java ?
 How is == operator different for objects and primitive types ?
 What will be the output of following code

Integer x = 1;
Integer y = 2;
System.out.println(x == y);

What if you change 1 to "1" and Integer to String?


 Q3. What is wrong with the following if statement ?

if(x==y || x.equals(y) {
}
Core Java2016-07-28 13:48:23

Ans. if x==y turns out to be true x.equals(y) will be true too. If x.equals(y) could be true even if x==y is true or not.

So the only possible outcomes are

1 || 1 = 1
0 || 1 = 1
0 || 0 = 0

i.e the outcome of x.equals(y)

check for x==y is not required in this if statement.

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   Like         Discuss         Correct / Improve     if statement  control statements  == and equals  ==  .equals   code optimization

Try 1 Question(s) Test


Related Questions

  Difference between == and .equals() ?
 What is the difference between = and == in Java ?
 How is == operator different for objects and primitive types ?
 What will be the output of following code

Integer x = 1;
Integer y = 2;
System.out.println(x == y);

What if you change 1 to "1" and Integer to String?



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