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| Core Java - Interview Questions and Answers for 'If statement' - 3 question(s) found - Order By Newest | ||||
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| Ans. x==y means that both references have same type and are pointing to same memory location and hence would always mean that they have same value. x.equals(y) is not required in this case. | ||||
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 Discuss Correct / Improve  if statement control statements == and equals == .equals code optimization | ||||
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 Difference between == and .equals() ? | ||||
| What is the difference between = and == in Java ? | ||||
| How is == operator different for objects and primitive types ? | ||||
| What will be the output of following code Integer x = 1; Integer y = 2; System.out.println(x == y); What if you change 1 to "1" and Integer to String? | ||||
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| Ans. if x==y turns out to be true x.equals(y) will be true too. If x.equals(y) could be true even if x==y is true or not. So the only possible outcomes are 1 || 1 = 1 0 || 1 = 1 0 || 0 = 0 i.e the outcome of x.equals(y) check for x==y is not required in this if statement. | ||||
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| Discuss Correct / Improve if statement control statements == and equals == .equals code optimization | ||||
| Try 1 Question(s) Test | ||||
| Related Questions | ||||
| Difference between == and .equals() ? | ||||
| What is the difference between = and == in Java ? | ||||
| How is == operator different for objects and primitive types ? | ||||
| What will be the output of following code Integer x = 1; Integer y = 2; System.out.println(x == y); What if you change 1 to "1" and Integer to String? | ||||
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| Ans. if statements nested within another if or else blocks are called nested if statements. if(condition1) { if(condition2){ } } | ||||
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| Discuss Correct / Improve if statement control statements nested if | ||||
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| Difference between if and switch ? Can we replace all switch statements with if statements ? | ||||
