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Ans. if x==y turns out to be true x.equals(y) will be true too. If x.equals(y) could be true even if x==y is true or not. So the only possible outcomes are 1 || 1 = 1 0 || 1 = 1 0 || 0 = 0 i.e the outcome of x.equals(y) check for x==y is not required in this if statement. | ||||
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![]() Integer x = 1; Integer y = 2; System.out.println(x == y); What if you change 1 to "1" and Integer to String? | ||||