What If we make the method as abstract in another Interface ?<br/><br/>public interface DefaultMethodInterface {<br/> default public void defaultMethod(){<br/> System.out.println("DefaultMethodInterface"); <br/> }<br/>}<br/><br/>public interface DefaultMethodInterface2 { <br/> public void defaultMethod(){<br/> System.out.println("DefaultMethodInterface2"); <br/> }<br/>}<br/><br/>public class HelloJava8 implements DefaultMethodInterface,DefaultMethodInterface2 {<br/> public static void main(String[] args){ <br/> DefaultMethodInterface defMethIn = new HelloJava8();<br/> defMethIn.defaultMethod();<br/> }<br/>} }
}

public interface DefaultMethodInterface2 {
public void defaultMethod(){
System.out.println("DefaultMethodInterface2");
}
}

public class HelloJava8 implements DefaultMethodInterface,DefaultMethodInterface2 {
public static void main(String[] args){
DefaultMethodInterface defMethIn = new HelloJava8();
defMethIn.defaultMethod();
}
}"> }
}

public interface DefaultMethodInterface2 {
public void defaultMethod(){
System.out.println("DefaultMethodInterface2");
}
}

public class HelloJava8 implements DefaultMethodInterface,DefaultMethodInterface2 {
public static void main(String[] args){
DefaultMethodInterface defMethIn = new HelloJava8();
defMethIn.defaultMethod();
}
}">
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 Q1. What If we make the method as abstract in another Interface ?

public interface DefaultMethodInterface {
default public void defaultMethod(){
System.out.println("DefaultMethodInterface");
}
}

public interface DefaultMethodInterface2 {
public void defaultMethod(){
System.out.println("DefaultMethodInterface2");
}
}

public class HelloJava8 implements DefaultMethodInterface,DefaultMethodInterface2 {
public static void main(String[] args){
DefaultMethodInterface defMethIn = new HelloJava8();
defMethIn.defaultMethod();
}
}
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Ans. Even then the Compiler will give error saying that there is a conflict.

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