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Interview Questions and Answers for 'Binary' - 10 question(s) found - Order By Newest

Advanced level question frequently asked in US based companies. Recently asked in EMC and Intuit.
  Q1. Can you provide some implementation of a Dictionary having large number of words ? Solution
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Ans. Simplest implementation we can have is a List wherein we can place ordered words and hence can perform Binary Search.

Other implementation with better search performance is to use HashMap with key as first character of the word and value as a LinkedList.

Further level up, we can have linked Hashmaps like ,

hashmap {
a ( key ) -> hashmap (key-aa , value (hashmap(key-aaa,value)
b ( key ) -> hashmap (key-ba , value (hashmap(key-baa,value)
....................................................................................
z( key ) -> hashmap (key-za , value (hashmap(key-zaa,value)
}

upto n levels ( where n is the average size of the word in dictionary.

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   Like      Discuss      Correct / Improve     java   collections   hashmap   binary search   search algorithm   advanced   architecture   data structure     Dell EMC   Intuit   Corporate Brokers  PWC India  Yahoo  Oracle        frequent

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 Q2. What are the pre-requisite for the collection to perform Binary Search ?
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Ans. 1. Collection should have an index for random access.
2. Collection should have ordered elements.

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   Like      Discuss      Correct / Improve     java   collections   search algorithm   search   binary search   at&t      intermediate


 Q3. What is the difference between >> and >>>?
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Ans. Both bitwise right shift operator ( >> ) and bitwise zero fill right shift operator ( >>> ) are used to shift the bits towards right. The difference is that >> will protect the sign bit whereas the >>> operator will not protect the sign bit. It always fills 0 in the sign bit.

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   Like      Discuss      Correct / Improve     java   operators   bitwise operators   binary shift   right shift


 Q4. Write a method to convert binary to a number ?Core Java
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info@buggybread.com
Ans.
convert(int binaryInt) {
   int sumValue=0;
   int multiple = 1;
   while(binaryInt > 0){
      binaryDigit = binaryInt%10;
      binaryInt = binaryInt /10;
      sumValue = sumValue + (binaryDigit * multiple);
      multiple = multiple * 2;
   }
   return sumValue;
}

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   Like      Discuss      Correct / Improve     java   binary   interesting question   coding


 Q5. Can we use Ordered Set for performing Binary Search ?
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Ans. We need to access values on the basis of an index in Binary search which is not possible with Sets.

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   Like      Discuss      Correct / Improve     java   sets   set   collections   binary search


Frequently asked to Fresh graduates.
 Q6. Write a program to implement Binary search ?Core Java2016-10-18 10:49:58

Ans. http://algs4.cs.princeton.edu/11model/BinarySearch.java.html

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   Like      Discuss      Correct / Improve     binary search  search     Cognizant (CTS)  Click Labs  Infoview Technologies  Mahindra Comviva  Acute Informatics      basic        frequent

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 Q7. What is a binary tree ?Algorithm2017-01-19 15:38:04

 This question was recently asked at 'Deloitte'.This question is still unanswered. Can you please provide an answer.


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   Like      Discuss      Correct / Improve     binary tree     Deloitte


 Q8. Write code to check if a Binary tree is symmetricalAlgorithm2017-03-03 14:29:12

 This question was recently asked at 'Amazon'.This question is still unanswered. Can you please provide an answer.


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   Like      Discuss      Correct / Improve     binary tree     Amazon


 Q9. How Cassandra provides better Read performance than Oracle Indices ?Database2017-08-18 09:39:56

Ans. Cassandra uses Hash Search which provides a look time of O(1) whereas Oracle Indices uses Binary Search that provide a lookup time of O(Log n).

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   Like      Discuss      Correct / Improve     cassandra  hash search  hash search vs binary search


 Q10. Binary Search requires that the collection should beAlgorithm
a. Sorted in Ascending Order
b. Sorted in Descending Order
c. Sorted in any Order
d. Unsorted

Ans.c. Sorted in any Order



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