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Interview Questions and Answers for 'Binary'  11 question(s) found  Order By Newest  
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Ans. Simplest implementation we can have is a List wherein we can place ordered words and hence can perform Binary Search. Other implementation with better search performance is to use HashMap with key as first character of the word and value as a LinkedList. Further level up, we can have linked Hashmaps like , hashmap { a ( key ) > hashmap (keyaa , value (hashmap(keyaaa,value) b ( key ) > hashmap (keyba , value (hashmap(keybaa,value) .................................................................................... z( key ) > hashmap (keyza , value (hashmap(keyzaa,value) } upto n levels ( where n is the average size of the word in dictionary.  
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Ans. 1. Collection should have an index for random access. 2. Collection should have ordered elements.  
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Ans. Binary tree is a tree in which each node has up to two children.Tree is a data structure composed of nodes.Each tree has a root node(not necessary in graph theory). The root node has zero or more child nodes.Each child node has zero or more child nodes, and so on.The tree cannot contain cycles.  
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Ans. Both bitwise right shift operator ( >> ) and bitwise zero fill right shift operator ( >>> ) are used to shift the bits towards right. The difference is that >> will protect the sign bit whereas the >>> operator will not protect the sign bit. It always fills 0 in the sign bit.  
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Ans. convert(int binaryInt) { int sumValue=0; int multiple = 1; while(binaryInt > 0){ binaryDigit = binaryInt%10; binaryInt = binaryInt /10; sumValue = sumValue + (binaryDigit * multiple); multiple = multiple * 2; } return sumValue; }  
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Ans. We need to access values on the basis of an index in Binary search which is not possible with Sets.  
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Ans. http://algs4.cs.princeton.edu/11model/BinarySearch.java.html  
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Ans. Cassandra uses Hash Search which provides a look time of O(1) whereas Oracle Indices uses Binary Search that provide a lookup time of O(Log n).  
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