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| Ans. convert(int binaryInt) { int sumValue=0; int multiple = 1; while(binaryInt > 0){ binaryDigit = binaryInt%10; binaryInt = binaryInt /10; sumValue = sumValue + (binaryDigit * multiple); multiple = multiple * 2; } return sumValue; } | ||||
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 If you have access to a function that returns a random integer from one to five, write another function which returns a random integer from one to seven. | ||||
