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Ans. public class Matrix { public static void main(String[] args) { int[][] matrix = { {1, 2, 3}, {4, 5, 6}, {7, 8, 9} }; Matrix.rotateMatrix(matrix); for (int i = 0; i < matrix.length; i ){ for (int j = 0; j < matrix.length; j ){ System.out.print(matrix[i][j] " "); } System.out.println(); } } public static void rotateMatrix(int[][] matrix){ int row = matrix.length; //first find the transpose of the matrix. for (int i = 0; i < row; i ){ for (int j = i; j < row; j ){ int temp = matrix[i][j]; matrix[i][j] = matrix[j][i]; matrix[j][i] = temp; } } //reverse each row for (int i = 0; i< row; i ){ for(int j = 0; j< row/2; j ){ int temp = matrix[i][j]; matrix[i][j] = matrix[i][row - 1 - j]; matrix[i][row - 1 - j] = temp; } } } } | ||||
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Ans. public class MyClass { static boolean binarySearch(int [] c, int start, int end, int value) { while (start <= end) { int mid = (start end) / 2; if (c[mid] == value) { return true; } if (c[mid] > value) { end = mid - 1; } else { start = mid 1; } } return false; } public static void main(String args[]) { int [] a = new int[] {1,2,4,6}; int [] b = new int[] {3,9}; int [] c = new int[] {2,4,5,6,7,9,10,12,15}; for (int i = 0; i < a.length; i ) { for(int j = 0; j < b.length; j ) { int value = a[i] b[j]; boolean find = binarySearch(c, 0, c.length - 1, value); if (find) { System.out.print(value " "); } } } } } | ||||
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This question was recently asked at 'Amdocs'.This question is still unanswered. Can you please provide an answer. | ||||
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Ans. Using Collections.sort() | ||||
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Ans. No | ||||
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Ans. https://www.geeksforgeeks.org/pojo-vs-java-beans/ | ||||
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