What will be the output of following code ? Base Interface public interface BaseInterface { int i = 4; } Derived Interfaces public interface DerivedInterface1 extends BaseInterface{ int i = 5; } public interface DerivedInterface2 extends BaseInterface{ int i=6; } Implementing Class public class Class implements DerivedInterface1,DerivedInterface2 { public static void main(String[] args){ System.out.println(BaseInterface.i); } } What will be the output upon executing main and Why ?

Java - Interview Questions and Answers

Q1. What will be the output of following code ?

Base Interface

public interface BaseInterface {
   int i = 4;
}

Derived Interfaces

public interface DerivedInterface1 extends BaseInterface{
   int i = 5;
}

public interface DerivedInterface2 extends BaseInterface{
   int i=6;
}

Implementing Class

public class Class implements DerivedInterface1,DerivedInterface2 {
   public static void main(String[] args){
      System.out.println(BaseInterface.i);
   }
}

What will be the output upon executing main and Why ?

Core Java

^{2017-01-26 13:42:29}

Ans. It will print 4 because member elements of an interface are implicitly static and hence the concept of overriding doesn't work.

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