Which method will get called if we call it as method(1) <br /> <br /> void method(int x ){};<br /> void method(int... x){};
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Java - Interview Questions and Answers

 Q1. Which method will get called if we call it as method(1)

void method(int x ){};
void method(int... x){};
Core Java2017-05-22 21:32:17

Ans. Though the call an be bind to either of these but in this case, 1st method will get priority and hence will be called.

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   Like         Discuss         Correct / Improve     var args  method  function  overloading  scjp  ocjp


Related Questions

 Which of the following are valid declarations

1. void method(int... x){};
2. void method(int.. x){};
3. void method(int.. .x){};
4. void method(int ...x){};
5. void method(int... x){};
6. void method(int ... x){};
7. void method(int x, int... y){};
8. void method(int... x, int y){};
9. void method(int... x,int... y){};
 What is the difference between these two method declarations ?

private static void method(String[] arg)

and

private static void method(String... arg)
  Which of the following is not valid var args declaration ?
 Can we overload method as following ?

void method(int... x){};
void method(int[] x){};
  Which of the following is false about var args ?
 What are var args ?

or

What is the use of var args ?
 Why following method declarations are not valid ?

void method(int... x, int y){};
void method(int... x,int... y){};
 Do you see any problem with this code

public class BuggyBread {

   public static void main(String[] args) {
      method("Hello","World");
   }

   private static void method(String... args){
      for(String arg:args){
         System.out.println(arg);
      }
   }
}
 Do you see any problem with this code

public class BuggyBread {

   public static void main(String[] args) {
      method();
   }

   private static void method(String... args){
      for(String arg:args){
         System.out.println(arg);
      }
   }
}



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