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Ans. http://www.programmingsimplified.com/java/source-code/java-program-armstrong-number | ||||
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Like Discuss Correct / Improve  program  code  coding  armstrong number Asked in 1 Companies | ||||
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Ans. package com.string; import java.util.Scanner; public class String13 { public static void main(String[] args) { System.out.println("Enter Sentence"); Scanner sc=new Scanner(System.in); String sentence=sc.nextLine(); String[] words=sentence.split(" "); int count=0; for (String string : words) { string.trim(); if(!string.equals("")){ count++; System.out.println(string " " count); } } } } | ||||
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Ans. int[] arr = {1,-1,2,-3,3,-4,4,5,6,-5,-6,-7,-8,8,9,-9}; List positiveNumbers = new ArrayList<>(); List negativeNumbers = new ArrayList<>(); for(int i = 0; i < arr.length(); i ){ if(I < 0){ negativeNumbers.add(i); } else { positiveNumbers.add(i); } } System.out.println("Positive Numbers:" + positiveNumbers); System.out.println("Negative Numbers:" + negativeNumbers); | ||||
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Ans. 500 is Internal Server Error 404 is resource not found 400 is Bad Request 403 is Forbidden 401 is Unauthorized 200 is OK | ||||
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Ans. https://www.tutorialspoint.com/javaexamples/thread_procon.htm | ||||
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Ans. General contract of hashCode is: 1.Whenever it is invoked on the same object more than once during an execution of a Java application, the hashCode method must consistently return the same integer, 2.If two objects are equal according to the equals(Object) method, then calling the hashCode method on each of the two objects must produce the same integer result. 3.It is not required that if two objects are unequal according to the equals(java.lang.Object) method, then calling the hashCode method on each of the two objects must produce distinct integer results. | ||||
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Frequently asked in high end product companies. | ||||
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Ans. https://www.geeksforgeeks.org/lru-cache-implementation/ | ||||
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Like Discuss Correct / Improve  cache  LRU cache  coding  code Asked in 10 Companies intermediate | ||||
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Ans. Yes its useless if we are not going to use its objects within Hash collection, For example - HashSet , HashMap. HashCode is used internally by these collections for Search. | ||||
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Ans. It will print 4 because member elements of an interface are implicitly static and hence the concept of overriding doesn't work. | ||||
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Ans. 10 | ||||
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Ans. public class Class{ public static void main(String[] args){ List<Integer> collector = new ArrayList(); Scanner scanner = new Scanner(System.in); int x = scanner.nextInt(); while(x != 0){ collector.add(x); x = scanner.nextInt(); } System.out.println(collector.stream().collect(Collectors.averagingInt(p->((Integer)p)))); } } | ||||
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Ans. public class Class{ public static void main(String[] args){ String string1 = "Hello I am Jack. I live in United States. I live in california state."; String string2 = "I live in"; if(string1.indexOf(string2) >= -1){ System.out.println("string2 is sub string of string1"); } else { System.out.println("string2 is not sub string of string1"); } } } | ||||
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Ans. public class Class{ public static void main(String[] args){ String string1 = "Hello I am Jack. I live in United States. I live in california state."; String string2 = "I live in"; int startIndex = 0; int endIndex = string1.length()-1; int countNoOfOccurences = 0; String remainingString = string1; while(startIndex < endIndex){ if(remainingString.indexOf(string2) != -1){ countNoOfOccurences++; startIndex = remainingString.indexOf(string2) + string2.length(); remainingString = remainingString.substring(startIndex); } else { break; } } System.out.println(countNoOfOccurences); } } | ||||
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Ans. public class Class { public static void main(String[] args) { String str = "mallam"; String firstHalf = str.substring(0, str.length() / 2); String secondHalf = str.substring(str.length() / 2); if (firstHalf.equals(new StringBuilder(secondHalf).reverse().toString())) { System.out.println("It's a Colidrome"); } else { System.out.println("It's not a Colidrome"); } } } | ||||
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Ans. public class Class{ public static void main(String[] args){ for(int i=1;i<= 100;i++){ if(i%3 == 0){ if(i%5 == 0){ System.out.println("FizzBuzz"); } System.out.println("Fizz"); } else if(i%5 == 0){ System.out.println("Buzz"); } else { System.out.println(i); } } } } | ||||
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Ans. public class BuggyBread { public static void main(String args[]) { Map<Character, Integer> countMap = new HashMap(); String str = "hello world"; for (char character : str.toCharArray()) { if (countMap.containsKey(character)) { countMap.put(character, countMap.get(character) + 1); } else { countMap.put(character, 1); } } System.out.println(countMap); } } | ||||
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Ans. public class BuggyBread{ public static void main (String args[]) { Set<Character> set = new HashSet(); Set<Character> setWithDuplicateChar = new HashSet(); String str = "hello world"; for(char character: str.toCharArray()){ if(set.contains(character)){ setWithDuplicateChar.add(character); } else { set.add(character); } } System.out.println(setWithDuplicateChar); } } | ||||
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This question was recently asked at 'Compro Technologies'.This question is still unanswered. Can you please provide an answer. | ||||
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Ans. 1. Object Level Reuse - private methods 2. Class Level Reuse - static methods 3. package level Reuse - default methods 4. Application Level Reuse - Classes 5. Multiple Applications Level Reuse - Libraries , Frameworks | ||||
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Ans. int arr[]={1,3,5,6,4,8,9,2,10}; Arrays.sort(); System.out.println(arr[arr.length-1]); | ||||
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Ans. public class BuggyBread { public static void main(String args[]) { String str1 = "we are what we repeatedly Do excellence, then, is not an act but a haBit"; String str2 = "we are what we repeatedly Do is"; String[] str1Words = str1.split(" "); String[] str2Words = str2.split(" "); Set str1WordsSet = new HashSet(); for(String word:str1Words){ str1WordsSet.add(word); } for(String word:str2Words){ if(str1WordsSet.contains(word)){ System.out.println(word); } } } } | ||||
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Ans. public class BuggyBread { public static void main(String args[]) { String str1 = "we are what we repeatedly Do excellence, then, is not an act but a haBit"; String str2 = "we are what we repeatedly Do is"; String[] str1Words = str1.split(" "); String[] str2Words = str2.split(" "); Set str1WordsSet = new HashSet(); for(String word:str1Words){ str1WordsSet.add(word); } int commonWordsCount = 0; for(String word:str2Words){ if(str1WordsSet.contains(word)){ commonWordsCount++; } } System.out.println(commonWordsCount); } } | ||||
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Ans. public class BuggyBread { public static void main(String args[]) { String str = "we are what we repeatedly Do excellence, then, is not an act but a haBit"; Set<String> wordSet = new LinkedHashSet(); // Using Linked Hash Set as we would like to retrieve words in the insertion order for(String word: str.split(" ")){ wordSet.add(word); } for(String word: wordSet){ System.out.print(word); System.out.print(" "); } } } | ||||
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Ans. public class BuggyBread { public static void main(String args[]) { String str = "we are what we repeatedly do excellence then is not an act but a haBit"; Set<String> wordSet = new TreeSet(); // Using Linked Hash Set as we would like to retrieve words in the insertion order for(String word: str.split(" ")){ wordSet.add(word); } for(String word: wordSet){ System.out.print(word); System.out.print(" "); } } } | ||||
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Ans. public class BuggyBread { public static void main(String args[]) { displayNumbersBetween(2,10); } private static void displayNumbersBetween(int start,int end){ if(start > end){ return ; } else { System.out.println(start); displayNumbersBetween(start+1,end); } } } | ||||
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Ans. public class BuggyBread { public static void main(String args[]) { displayNumbersBetween(5,7); } private static void displayNumbersBetween(int start,int end){ if(start > end){ return ; } else { for(int x=1;x<=start;x++){ System.out.print("*"); } System.out.println(""); displayNumbersBetween(start+1,end); } } } | ||||
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Ans. public class BuggyBread { public static void main(String args[]) { for(int x=1;x<=10;x++){ for(int y=1;y<=x;y++){ System.out.print("*"); } System.out.println(""); } } } | ||||
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Ans. public class Class{ public static void main(String[] args){ String str = "xyz@123.com"; if(!str.contains("@") && !str.contains(".") && (str.indexOf('.') < str.indexOf('@'))){ System.out.println("Not a Valid Email Address"); } } } | ||||
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Ans. public class Class{ public static void main(String[] args){ String str = "xyz123.co@m"; if(str.indexOf('.') < str.indexOf('@')){ System.out.println("Not a Valid Email Address"); } } } | ||||
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This question was recently asked at 'karya technology'.This question is still unanswered. Can you please provide an answer. | ||||
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Like Discuss Correct / Improve  coding  code Asked in 1 Companies | ||||