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Q2162. What is the command to change file / folder permissions ? What command should we use if we would like to give most liberal position on the file ?
Ans. A program that uses HTTP for serving files that create web pages for users in response to their requests that are sent by the HTTP clients of their computer is called as a web server.
Web - Server Types
Apache HTTP Server by the Apache Software Foundation
Internet Information Service from Microsoft
Sun Java System Web Server
Jigsaw Server.
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Ans. // Java code for serialization and deserialization
// of a Java object
import java.io.*;
class Demo implements java.io.Serializable
{
public int a;
public String b;
// Default constructor
public Demo(int a, String b)
{
this.a = a;
this.b = b;
}
}
class Test
{
public static void main(String[] args)
{
Demo object = new Demo(1, "geeksforgeeks");
String filename = "file.ser";
// Serialization
try
{
//Saving of object in a file
FileOutputStream file = new FileOutputStream(filename);
ObjectOutputStream out = new ObjectOutputStream(file);
// Method for serialization of object
out.writeObject(object);
out.close();
file.close();
System.out.println("Object has been serialized");
}
catch(IOException ex)
{
System.out.println("IOException is caught");
}
Demo object1 = null;
// Deserialization
try
{
// Reading the object from a file
FileInputStream file = new FileInputStream(filename);
ObjectInputStream in = new ObjectInputStream(file);
// Method for deserialization of object
object1 = (Demo)in.readObject();
in.close();
file.close();
System.out.println("Object has been deserialized ");
System.out.println("a = " object1.a);
System.out.println("b = " object1.b);
}
catch(IOException ex)
{
System.out.println("IOException is caught");
}
catch(ClassNotFoundException ex)
{
System.out.println("ClassNotFoundException is caught");
}
}
}
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Q2180. In a web application you notice freezes for several seconds during high load. What could be the most likely reasons? How would you troubleshoot them ?
This question is still unanswered. Can you please provide an answer.
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Ans. Immutable objects relieves us from the problems of inconsistencies and security and helps with better read performance but at the same time are write performance and storage overheads. In case any modification is required , a new object is created and thus creating multiple copies of it.
This is the reason we use StringBuffer / StringBuilder when we have to append some text multiple times and then create a String out of it.
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Ans. Yes , but only the read performance in case we don't need to modify it much. In case we need to modify it a lot , it creates write performance overheads as we would need to create many news objects instead of just changing one.
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Ans. int main ()
{
int a []={1..n};
int miss=getMiss (a,n);
Printf ("%d",miss);
}
getMiss (int a [],int n){
int I,total;
total=(n 1)*(n 2);
for (i = 0; i < n; i++)
total -= a[i];
return total;
}
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Ans. import java.util.Scanner;
public class Prime
{
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in);
System.out.print("Enter n to compute the nth prime number: ");
int nth = sc.nextInt();
int num, count, i;
num=1;
count=0;
while (count < nth){
num=num 1;
for (i = 2; i <= num; i )
{
if (num % i == 0)
{
break;
}
}
if ( i == num)
{
count = count 1;
}
}
System.out.println("Value of nth prime: " num);
}
}
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Ans. Class lengofstring {
Public static void main(String[] arr) {
int i = 0;
String s = "hello world!";
for (char C: s.toCharArray()) i;
System.out.println("Length: "
i);
}
}
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