Do you see any problem with this code
public class BuggyBread {
public static void main(String[] args) {
method("Hello");
}
private static void method(String... args){
for(String arg:args){
System.out.println(arg);
}
}
private static void method(String arg){
System.out.println(arg);
}
}
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Interview Questions and Answers
Q1.
Do you see any problem with this code
public class BuggyBread {
public static void main(String[] args) {
method("Hello");
}
private static void method(String... args){
for(String arg:args){
System.out.println(arg);
}
}
private static void method(String arg){
System.out.println(arg);
}
}
Core Java
Ans. It will compile fine and the method call will bind to method with specific argument and not with var arg
i.e private static void method(String arg)
It will print "Hello" upon execution
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:
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 var args  methods  method declarations  functions
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Related Questions
Which of the following are valid declarations
1. void method(int... x){};
2. void method(int.. x){};
3. void method(int.. .x){};
4. void method(int ...x){};
5. void method(int... x){};
6. void method(int ... x){};
7. void method(int x, int... y){};
8. void method(int... x, int y){};
9. void method(int... x,int... y){};
What is the difference between these two method declarations ?
private static void method(String[] arg)
and
private static void method(String... arg)
Can we overload method as following ?
void method(int... x){};
void method(int[] x){};
Which of the following is not valid var args declaration ?
Do you prefer using var args ?
Which of the following is false about var args ?
What are var args ?
or
What is the use of var args ?
Why following method declarations are not valid ?
void method(int... x, int y){};
void method(int... x,int... y){};
Which method will get called if we call it as method(1)
void method(int x ){};
void method(int... x){};
Do you see any problem with this code
public class BuggyBread {
public static void main(String[] args) {
method("Hello","World");
}
private static void method(String... args){
for(String arg:args){
System.out.println(arg);
}
}
}
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