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Ans. NumberFormatException is the exception that Java throws when we try to convert one data type to the Number data type but the value is not parsable to be a Number.
For example , the following code will result in the NumberFormatException
String string = "Buggy";
int strtoInt = Integer.parseInt(string);
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Ans. Spliterator has better performance potential than iterators but only if the potential is used. Spliterator can iterate streams in parallel as well as in sequence whereas iterator can only iterate in sequence.
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Ans. Java provides a faster allocation mechanism but at the cost of expensive deallocation. Deallocation in java is done by mechanism called garbage collection that runs periodically to free up unclaimed memory space , which actually slows down the application. Hence Java is usually faster if memory is not of concern and sufficiently large memory can be allocated to an application.
C/C++ on other hand have equal cost of allocation and de-allocation.
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Ans. Collections in java is a framework of classes that provides an abstracted data structure to store and manipulate the group of objects. Each class is unique in the way it stores , search , sort and modify the elements.
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Ans. Everytime an object is serialized the java serialization mechanism automatically computes a hash value by passing the meta information for the class. This id is used during deserialization to verify that the sender and receiver of a serialized object have loaded classes for that object that are compatible with respect to serialization
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Ans. In first case the whole loop will terminate as soon as any exception happens in the method calculate ( assuming calculate method is not handling its exception and those are thrown back at the calling method )
In Second case exception will be caught for individual iteration and hence it wont break the loop and will continue for the next iteration.
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Ans. Spring Security is a powerful and highly customizable authentication and access control framework. It is the de facto standard for securing Spring-based applications.
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Ans. No, there is no relationship between web.xml and spring.xml but you have to configure spring.xml in web.xml in order initialize beans when application starts up
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Ans. By keeping some sort of storage at the client side for each request and then matching it up against the response received to make sure that the request was well received.
A queue can be used for this purpose.
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Ans. a. Inform the stake holders that the issue is being worked upon.
b. Login to server to see if its responding.
c. Access Application and Web Server logs to see if the application is receiving requests.
d. If not, Involve the appropriate Network Team.
e. Inform the stakeholders regarding the progress.
f. Bounce the web / application server instance , if required.
g. Close the ticket with the steps taken to resolve the problem.
h. Complete the RCA ( Root Cause Analysis ) and submit the report to stake holders.
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